Re: pinhole RE: Centripetal Force at Equator

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From: Paul Doherty (pauld@exploratorium.edu)
Date: Sat Nov 13 1999 - 16:04:40 PST 

Message-Id: <l03110722b453ac86888e@[192.174.2.173]>
Date: Sat, 13 Nov 1999 16:04:40 -0800
From: Paul Doherty <pauld@exploratorium.edu>
Subject: Re: pinhole RE: Centripetal Force at Equator

In simple form

The centripetal force needed on a person standing on the equator is 2.3 N
because the person weighs 700 N and the centripetal force is about 1/300 of
the weight.
an object that weighs 2.3 N would have a centripetal force 1/300 of 2.3 N
or about 0.006 N.

The force is a function of the mass.

Paul Doherty

Paul "But it is more complicated than that!" Doherty,
Senior Staff Scientist, The Exploratorium.
pauld@exploratorium.edu, www.exo.net/~pauld

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